Base | Representation |
---|---|
bin | 11101110010101001101101… |
… | …100111101100101100011101 |
3 | 122011220210010121101112110220 |
4 | 131302221231213230230131 |
5 | 114133144340013030010 |
6 | 1142355351300351553 |
7 | 36412115424352626 |
oct | 3562515547545435 |
9 | 564823117345426 |
10 | 131024111455005 |
11 | 3882601714113a |
12 | 128414259a55b9 |
13 | 581569cc71762 |
14 | 244d85a974a4d |
15 | 10233879b9970 |
hex | 772a6d9ecb1d |
131024111455005 has 16 divisors (see below), whose sum is σ = 209773048268160. Its totient is φ = 69834702795968.
The previous prime is 131024111454917. The next prime is 131024111455031. The reversal of 131024111455005 is 500554111420131.
It is a cyclic number.
It is not a de Polignac number, because 131024111455005 - 28 = 131024111454749 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2801432922 + ... + 2801479691.
It is an arithmetic number, because the mean of its divisors is an integer number (13110815516760).
Almost surely, 2131024111455005 is an apocalyptic number.
131024111455005 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
131024111455005 is a deficient number, since it is larger than the sum of its proper divisors (78748936813155).
131024111455005 is a wasteful number, since it uses less digits than its factorization.
131024111455005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5602914180.
The product of its (nonzero) digits is 12000, while the sum is 33.
Adding to 131024111455005 its reverse (500554111420131), we get a palindrome (631578222875136).
The spelling of 131024111455005 in words is "one hundred thirty-one trillion, twenty-four billion, one hundred eleven million, four hundred fifty-five thousand, five".
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