Base | Representation |
---|---|
bin | 11000011001111011… |
… | …01110110111010111 |
3 | 1020211010111110020202 |
4 | 30030331232313113 |
5 | 203313204124343 |
6 | 10004050051115 |
7 | 642455441426 |
oct | 141475566727 |
9 | 36733443222 |
10 | 13102411223 |
11 | 5613a73530 |
12 | 2657b79a9b |
13 | 130a67ab65 |
14 | 8c41c72bd |
15 | 51a430db8 |
hex | 30cf6edd7 |
13102411223 has 4 divisors (see below), whose sum is σ = 14293539528. Its totient is φ = 11911282920.
The previous prime is 13102411193. The next prime is 13102411243. The reversal of 13102411223 is 32211420131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13102411223 - 214 = 13102394839 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13102411195 and 13102411204.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13102411243) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 595564136 + ... + 595564157.
It is an arithmetic number, because the mean of its divisors is an integer number (3573384882).
Almost surely, 213102411223 is an apocalyptic number.
13102411223 is a deficient number, since it is larger than the sum of its proper divisors (1191128305).
13102411223 is a wasteful number, since it uses less digits than its factorization.
13102411223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1191128304.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 13102411223 its reverse (32211420131), we get a palindrome (45313831354).
The spelling of 13102411223 in words is "thirteen billion, one hundred two million, four hundred eleven thousand, two hundred twenty-three".
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