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131024143 = 193167853
BaseRepresentation
bin1111100111101…
…00010100001111
3100010112201100001
413303310110033
5232020233033
621000145131
73150454405
oct763642417
9303481301
10131024143
1167a61418
1237a681a7
13211b69a3
1413589475
15b781e7d
hex7cf450f

131024143 has 4 divisors (see below), whose sum is σ = 131093928. Its totient is φ = 130954360.

The previous prime is 131024119. The next prime is 131024149. The reversal of 131024143 is 341420131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131024143 - 25 = 131024111 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131024143.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131024149) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31996 + ... + 35857.

It is an arithmetic number, because the mean of its divisors is an integer number (32773482).

Almost surely, 2131024143 is an apocalyptic number.

131024143 is a deficient number, since it is larger than the sum of its proper divisors (69785).

131024143 is an equidigital number, since it uses as much as digits as its factorization.

131024143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 69784.

The product of its (nonzero) digits is 288, while the sum is 19.

The square root of 131024143 is about 11446.5777855217. The cubic root of 131024143 is about 507.9065059822.

Adding to 131024143 its reverse (341420131), we get a palindrome (472444274).

The spelling of 131024143 in words is "one hundred thirty-one million, twenty-four thousand, one hundred forty-three".

Divisors: 1 1931 67853 131024143