Search a number
-
+
1310243011111 = 2561295115559
BaseRepresentation
bin10011000100010000100…
…100011011101000100111
311122020222002101022221001
4103010100210123220213
5132431334202323421
62441530050534131
7163443020556466
oct23042044335047
94566862338831
101310243011111
11465742027031
12191b25897347
139672b24b168
14475b7ac89dd
15241382d6691
hex1311091ba27

1310243011111 has 4 divisors (see below), whose sum is σ = 1310248382800. Its totient is φ = 1310237639424.

The previous prime is 1310243011067. The next prime is 1310243011141. The reversal of 1310243011111 is 1111103420131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1310243011111 - 211 = 1310243009063 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310243011141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2301651 + ... + 2813908.

It is an arithmetic number, because the mean of its divisors is an integer number (327562095700).

Almost surely, 21310243011111 is an apocalyptic number.

1310243011111 is a deficient number, since it is larger than the sum of its proper divisors (5371689).

1310243011111 is an equidigital number, since it uses as much as digits as its factorization.

1310243011111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5371688.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 1310243011111 its reverse (1111103420131), we get a palindrome (2421346431242).

The spelling of 1310243011111 in words is "one trillion, three hundred ten billion, two hundred forty-three million, eleven thousand, one hundred eleven".

Divisors: 1 256129 5115559 1310243011111