1310244051133 has 4 divisors (see below), whose sum is σ = 1310386679680. Its totient is φ = 1310101422588.

The previous prime is 1310244051131. The next prime is 1310244051209. The reversal of 1310244051133 is 3311504420131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1310244051133 - 2¹ = 1310244051131 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310244051131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71300493 + ... + 71318866.

It is an arithmetic number, because the mean of its divisors is an integer number (327596669920).

Almost surely, 2^{1310244051133} is an apocalyptic number.

It is an amenable number.

1310244051133 is a deficient number, since it is larger than the sum of its proper divisors (142628547).

1310244051133 is an equidigital number, since it uses as much as digits as its factorization.

1310244051133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 142628546.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 1310244051133 its reverse (3311504420131), we get a palindrome (4621748471264).

The spelling of 1310244051133 in words is "one trillion, three hundred ten billion, two hundred forty-four million, fifty-one thousand, one hundred thirty-three".