Base | Representation |
---|---|
bin | 111101000000111110… |
… | …0111010111010010001 |
3 | 110112012122122112202101 |
4 | 1322001330322322101 |
5 | 4121321441442211 |
6 | 140105523320401 |
7 | 12316012150201 |
oct | 1720174727221 |
9 | 415178575671 |
10 | 131029249681 |
11 | 50629660700 |
12 | 21489520101 |
13 | c4821b3305 |
14 | 64b006c401 |
15 | 361d3c15c1 |
hex | 1e81f3ae91 |
131029249681 has 48 divisors (see below), whose sum is σ = 159178017600. Its totient is φ = 107326961280.
The previous prime is 131029249661. The next prime is 131029249693. The reversal of 131029249681 is 186942920131.
It is not a de Polignac number, because 131029249681 - 223 = 131020861073 is a prime.
It is a super-2 number, since 2×1310292496812 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (131029249621) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 4452291 + ... + 4481623.
It is an arithmetic number, because the mean of its divisors is an integer number (3316208700).
Almost surely, 2131029249681 is an apocalyptic number.
131029249681 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
131029249681 is a deficient number, since it is larger than the sum of its proper divisors (28148767919).
131029249681 is a wasteful number, since it uses less digits than its factorization.
131029249681 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29470 (or 29459 counting only the distinct ones).
The product of its (nonzero) digits is 186624, while the sum is 46.
The spelling of 131029249681 in words is "one hundred thirty-one billion, twenty-nine million, two hundred forty-nine thousand, six hundred eighty-one".
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