Base | Representation |
---|---|
bin | 111101000000111111… |
… | …1110010010101101001 |
3 | 110112012201001201101001 |
4 | 1322001333302111221 |
5 | 4121322140013001 |
6 | 140105551355001 |
7 | 12316021426504 |
oct | 1720177622551 |
9 | 415181051331 |
10 | 131030001001 |
11 | 5062a024129 |
12 | 21489822a61 |
13 | c4823b7293 |
14 | 64b01c613b |
15 | 361d4be001 |
hex | 1e81ff2569 |
131030001001 has 4 divisors (see below), whose sum is σ = 131897749504. Its totient is φ = 130162252500.
The previous prime is 131030000911. The next prime is 131030001007. The reversal of 131030001001 is 100100030131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 131030001001 - 227 = 130895783273 is a prime.
It is a super-4 number, since 4×1310300010014 (a number of 46 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131030001007) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 433874025 + ... + 433874326.
It is an arithmetic number, because the mean of its divisors is an integer number (32974437376).
Almost surely, 2131030001001 is an apocalyptic number.
It is an amenable number.
131030001001 is a deficient number, since it is larger than the sum of its proper divisors (867748503).
131030001001 is an equidigital number, since it uses as much as digits as its factorization.
131030001001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 867748502.
The product of its (nonzero) digits is 9, while the sum is 10.
Adding to 131030001001 its reverse (100100030131), we get a palindrome (231130031132).
The spelling of 131030001001 in words is "one hundred thirty-one billion, thirty million, one thousand, one".
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