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13103013330002 = 26551506665001
BaseRepresentation
bin1011111010101100100001…
…1101000111110001010010
31201101122011112020220012002
42332223020131013301102
53204134432403030002
643511235145434002
72521442612431511
oct276531035076122
951348145226162
1013103013330002
1141a1a58480272
12157755079b902
137407bb86885b
1433429135c678
1517ac8d1ea002
hexbeac8747c52

13103013330002 has 4 divisors (see below), whose sum is σ = 19654519995006. Its totient is φ = 6551506665000.

The previous prime is 13103013329929. The next prime is 13103013330007. The reversal of 13103013330002 is 20003331030131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 8418650023081 + 4684363306921 = 2901491^2 + 2164339^2 .

It is not an unprimeable number, because it can be changed into a prime (13103013330007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3275753332499 + ... + 3275753332502.

Almost surely, 213103013330002 is an apocalyptic number.

13103013330002 is a deficient number, since it is larger than the sum of its proper divisors (6551506665004).

13103013330002 is an equidigital number, since it uses as much as digits as its factorization.

13103013330002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6551506665003.

The product of its (nonzero) digits is 486, while the sum is 20.

Adding to 13103013330002 its reverse (20003331030131), we get a palindrome (33106344360133).

The spelling of 13103013330002 in words is "thirteen trillion, one hundred three billion, thirteen million, three hundred thirty thousand, two".

Divisors: 1 2 6551506665001 13103013330002