13103041114 has 4 divisors (see below), whose sum is σ = 19654561674. Its totient is φ = 6551520556.

The previous prime is 13103041093. The next prime is 13103041169. The reversal of 13103041114 is 41114030131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 41114030131 = 709 ⋅57988759.

It can be written as a sum of positive squares in only one way, i.e., 6595876225 + 6507164889 = 81215^2 + 80667^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13103041091 and 13103041100.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3275760277 + ... + 3275760280.

Almost surely, 2^13103041114 is an apocalyptic number.

13103041114 is a deficient number, since it is larger than the sum of its proper divisors (6551520560).

13103041114 is an equidigital number, since it uses as much as digits as its factorization.

13103041114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6551520559.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 13103041114 its reverse (41114030131), we get a palindrome (54217071245).

The spelling of 13103041114 in words is "thirteen billion, one hundred three million, forty-one thousand, one hundred fourteen".