Base | Representation |
---|---|
bin | 11000011010000000… |
… | …10110001001111011 |
3 | 1020211011210021012021 |
4 | 30031000112021323 |
5 | 203313343041233 |
6 | 10004112455311 |
7 | 642464324233 |
oct | 141500261173 |
9 | 36734707167 |
10 | 13103096443 |
11 | 56143a1328 |
12 | 265824a537 |
13 | 130a85aa08 |
14 | 8c4324cc3 |
15 | 51a518e2d |
hex | 30d01627b |
13103096443 has 4 divisors (see below), whose sum is σ = 13873866840. Its totient is φ = 12332326048.
The previous prime is 13103096437. The next prime is 13103096449. The reversal of 13103096443 is 34469030131.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (13103096437) and next prime (13103096449).
It is not a de Polignac number, because 13103096443 - 29 = 13103095931 is a prime.
It is a super-2 number, since 2×131030964432 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13103096399 and 13103096408.
It is not an unprimeable number, because it can be changed into a prime (13103096449) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 385385173 + ... + 385385206.
It is an arithmetic number, because the mean of its divisors is an integer number (3468466710).
Almost surely, 213103096443 is an apocalyptic number.
13103096443 is a deficient number, since it is larger than the sum of its proper divisors (770770397).
13103096443 is an equidigital number, since it uses as much as digits as its factorization.
13103096443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 770770396.
The product of its (nonzero) digits is 23328, while the sum is 34.
The spelling of 13103096443 in words is "thirteen billion, one hundred three million, ninety-six thousand, four hundred forty-three".
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