Search a number
-
+
13103101023 = 34367700341
BaseRepresentation
bin11000011010000000…
…10111010001011111
31020211011210111110220
430031000113101133
5203313343213043
610004112532423
7642464343465
oct141500272137
936734714426
1013103101023
1156143a4811
122658251113
13130a85cb1c
148c4326835
1551a51a483
hex30d01745f

13103101023 has 4 divisors (see below), whose sum is σ = 17470801368. Its totient is φ = 8735400680.

The previous prime is 13103100947. The next prime is 13103101031. The reversal of 13103101023 is 32010130131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13103101023 - 28 = 13103100767 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13103100993 and 13103101011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13103101073) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2183850168 + ... + 2183850173.

It is an arithmetic number, because the mean of its divisors is an integer number (4367700342).

Almost surely, 213103101023 is an apocalyptic number.

13103101023 is a deficient number, since it is larger than the sum of its proper divisors (4367700345).

13103101023 is an equidigital number, since it uses as much as digits as its factorization.

13103101023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4367700344.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 13103101023 its reverse (32010130131), we get a palindrome (45113231154).

The spelling of 13103101023 in words is "thirteen billion, one hundred three million, one hundred one thousand, twenty-three".

Divisors: 1 3 4367700341 13103101023