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131031043020043 = 307426811215049
BaseRepresentation
bin11101110010110000001010…
…110001100001010100001011
3122011221110000200100112010221
4131302300022301201110023
5114133303034003120133
61142402455152050511
736412452252604225
oct3562601261412413
9564843020315127
10131031043020043
1138828a538a3591
121284283b233a37
13581623603632a
14244dd17399415
1510236412b6a2d
hex772c0ac6150b

131031043020043 has 4 divisors (see below), whose sum is σ = 131457854235400. Its totient is φ = 130604231804688.

The previous prime is 131031043020001. The next prime is 131031043020049. The reversal of 131031043020043 is 340020340130131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131031043020043 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131031043020049) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 213405607218 + ... + 213405607831.

It is an arithmetic number, because the mean of its divisors is an integer number (32864463558850).

Almost surely, 2131031043020043 is an apocalyptic number.

131031043020043 is a deficient number, since it is larger than the sum of its proper divisors (426811215357).

131031043020043 is an equidigital number, since it uses as much as digits as its factorization.

131031043020043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 426811215356.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 131031043020043 its reverse (340020340130131), we get a palindrome (471051383150174).

The spelling of 131031043020043 in words is "one hundred thirty-one trillion, thirty-one billion, forty-three million, twenty thousand, forty-three".

Divisors: 1 307 426811215049 131031043020043