Base | Representation |
---|---|
bin | 11101110010110000001010… |
… | …110001100001010100001011 |
3 | 122011221110000200100112010221 |
4 | 131302300022301201110023 |
5 | 114133303034003120133 |
6 | 1142402455152050511 |
7 | 36412452252604225 |
oct | 3562601261412413 |
9 | 564843020315127 |
10 | 131031043020043 |
11 | 38828a538a3591 |
12 | 1284283b233a37 |
13 | 581623603632a |
14 | 244dd17399415 |
15 | 10236412b6a2d |
hex | 772c0ac6150b |
131031043020043 has 4 divisors (see below), whose sum is σ = 131457854235400. Its totient is φ = 130604231804688.
The previous prime is 131031043020001. The next prime is 131031043020049. The reversal of 131031043020043 is 340020340130131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131031043020043 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131031043020049) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 213405607218 + ... + 213405607831.
It is an arithmetic number, because the mean of its divisors is an integer number (32864463558850).
Almost surely, 2131031043020043 is an apocalyptic number.
131031043020043 is a deficient number, since it is larger than the sum of its proper divisors (426811215357).
131031043020043 is an equidigital number, since it uses as much as digits as its factorization.
131031043020043 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 426811215356.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 131031043020043 its reverse (340020340130131), we get a palindrome (471051383150174).
The spelling of 131031043020043 in words is "one hundred thirty-one trillion, thirty-one billion, forty-three million, twenty thousand, forty-three".
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