Base | Representation |
---|---|
bin | 111101000001000001… |
… | …1111110111101111111 |
3 | 110112012210010121201021 |
4 | 1322002003332331333 |
5 | 4121322430220221 |
6 | 140110031125011 |
7 | 12316033661425 |
oct | 1720203767577 |
9 | 415183117637 |
10 | 131031101311 |
11 | 5062a705880 |
12 | 2148a073767 |
13 | c4826b1056 |
14 | 64b03d1115 |
15 | 361d63a041 |
hex | 1e820fef7f |
131031101311 has 4 divisors (see below), whose sum is σ = 142943019624. Its totient is φ = 119119183000.
The previous prime is 131031101309. The next prime is 131031101317. The reversal of 131031101311 is 113101130131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131031101311 - 21 = 131031101309 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131031101317) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5955959140 + ... + 5955959161.
It is an arithmetic number, because the mean of its divisors is an integer number (35735754906).
Almost surely, 2131031101311 is an apocalyptic number.
131031101311 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
131031101311 is a deficient number, since it is larger than the sum of its proper divisors (11911918313).
131031101311 is a wasteful number, since it uses less digits than its factorization.
131031101311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11911918312.
The product of its (nonzero) digits is 27, while the sum is 16.
Adding to 131031101311 its reverse (113101130131), we get a palindrome (244132231442).
The spelling of 131031101311 in words is "one hundred thirty-one billion, thirty-one million, one hundred one thousand, three hundred eleven".
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