131031111410233 has 4 divisors (see below), whose sum is σ = 131112649128960. Its totient is φ = 130949573691508.

The previous prime is 131031111410123. The next prime is 131031111410237. The reversal of 131031111410233 is 332014111130131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131031111410233 - 2⁹ = 131031111409721 is a prime.

It is a super-2 number, since 2×131031111410233² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131031111410198 and 131031111410207.

It is not an unprimeable number, because it can be changed into a prime (131031111410237) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40768856953 + ... + 40768860166.

It is an arithmetic number, because the mean of its divisors is an integer number (32778162282240).

Almost surely, 2^{131031111410233} is an apocalyptic number.

It is an amenable number.

131031111410233 is a deficient number, since it is larger than the sum of its proper divisors (81537718727).

131031111410233 is an equidigital number, since it uses as much as digits as its factorization.

131031111410233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81537718726.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 131031111410233 its reverse (332014111130131), we get a palindrome (463045222540364).

The spelling of 131031111410233 in words is "one hundred thirty-one trillion, thirty-one billion, one hundred eleven million, four hundred ten thousand, two hundred thirty-three".