131031223310041 has 4 divisors (see below), whose sum is σ = 131031518602192. Its totient is φ = 131030928017892.

The previous prime is 131031223310027. The next prime is 131031223310087. The reversal of 131031223310041 is 140013322130131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131031223310041 - 2¹¹ = 131031223307993 is a prime.

It is a super-2 number, since 2×131031223310041² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131031223309988 and 131031223310015.

It is not an unprimeable number, because it can be changed into a prime (131031223316041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 146979471 + ... + 147868276.

It is an arithmetic number, because the mean of its divisors is an integer number (32757879650548).

Almost surely, 2^{131031223310041} is an apocalyptic number.

It is an amenable number.

131031223310041 is a deficient number, since it is larger than the sum of its proper divisors (295292151).

131031223310041 is an equidigital number, since it uses as much as digits as its factorization.

131031223310041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 295292150.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 131031223310041 its reverse (140013322130131), we get a palindrome (271044545440172).

The spelling of 131031223310041 in words is "one hundred thirty-one trillion, thirty-one billion, two hundred twenty-three million, three hundred ten thousand, forty-one".