Base | Representation |
---|---|
bin | 11000011010000001… |
… | …10001111011011111 |
3 | 1020211012000001020202 |
4 | 30031000301323133 |
5 | 203313410211312 |
6 | 10004115134115 |
7 | 642465310013 |
oct | 141500617337 |
9 | 36735001222 |
10 | 13103210207 |
11 | 561446984a |
12 | 26582a433b |
13 | 130a89a729 |
14 | 8c4354543 |
15 | 51a53c9c2 |
hex | 30d031edf |
13103210207 has 4 divisors (see below), whose sum is σ = 13873987296. Its totient is φ = 12332433120.
The previous prime is 13103210201. The next prime is 13103210227. The reversal of 13103210207 is 70201230131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13103210207 - 26 = 13103210143 is a prime.
It is a super-3 number, since 3×131032102073 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13103210201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 385388519 + ... + 385388552.
It is an arithmetic number, because the mean of its divisors is an integer number (3468496824).
Almost surely, 213103210207 is an apocalyptic number.
13103210207 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
13103210207 is a deficient number, since it is larger than the sum of its proper divisors (770777089).
13103210207 is an equidigital number, since it uses as much as digits as its factorization.
13103210207 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 770777088.
The product of its (nonzero) digits is 252, while the sum is 20.
Adding to 13103210207 its reverse (70201230131), we get a palindrome (83304440338).
The spelling of 13103210207 in words is "thirteen billion, one hundred three million, two hundred ten thousand, two hundred seven".
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