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131033230012121 = 239954619937479
BaseRepresentation
bin11101110010110010001101…
…001000001110111011011001
3122011221122200002120020021112
4131302302031020032323121
5114133322023340341441
61142403500154550105
736412560406665353
oct3562621510167331
9564848602506245
10131033230012121
1138829976349058
121284314b738335
1358164c4161c98
142450083a0c0d3
15102371d2b44eb
hex772c8d20eed9

131033230012121 has 4 divisors (see below), whose sum is σ = 131087849952000. Its totient is φ = 130978610072244.

The previous prime is 131033230012117. The next prime is 131033230012123. The reversal of 131033230012121 is 121210032330131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131033230012121 - 22 = 131033230012117 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131033230012123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27309966341 + ... + 27309971138.

It is an arithmetic number, because the mean of its divisors is an integer number (32771962488000).

Almost surely, 2131033230012121 is an apocalyptic number.

It is an amenable number.

131033230012121 is a deficient number, since it is larger than the sum of its proper divisors (54619939879).

131033230012121 is an equidigital number, since it uses as much as digits as its factorization.

131033230012121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 54619939878.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 131033230012121 its reverse (121210032330131), we get a palindrome (252243262342252).

The spelling of 131033230012121 in words is "one hundred thirty-one trillion, thirty-three billion, two hundred thirty million, twelve thousand, one hundred twenty-one".

Divisors: 1 2399 54619937479 131033230012121