Base | Representation |
---|---|
bin | 11101110010110010001101… |
… | …001000001110111011010101 |
3 | 122011221122200002120020021101 |
4 | 131302302031020032323111 |
5 | 114133322023340341432 |
6 | 1142403500154550101 |
7 | 36412560406665346 |
oct | 3562621510167325 |
9 | 564848602506241 |
10 | 131033230012117 |
11 | 38829976349054 |
12 | 1284314b738331 |
13 | 58164c4161c94 |
14 | 2450083a0c0cd |
15 | 102371d2b44e7 |
hex | 772c8d20eed5 |
131033230012117 has 2 divisors, whose sum is σ = 131033230012118. Its totient is φ = 131033230012116.
The previous prime is 131033230012103. The next prime is 131033230012123. The reversal of 131033230012117 is 711210032330131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 120800454337476 + 10232775674641 = 10990926^2 + 3198871^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131033230012117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131033230012177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65516615006058 + 65516615006059.
It is an arithmetic number, because the mean of its divisors is an integer number (65516615006059).
Almost surely, 2131033230012117 is an apocalyptic number.
It is an amenable number.
131033230012117 is a deficient number, since it is larger than the sum of its proper divisors (1).
131033230012117 is an equidigital number, since it uses as much as digits as its factorization.
131033230012117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2268, while the sum is 28.
Adding to 131033230012117 its reverse (711210032330131), we get a palindrome (842243262342248).
The spelling of 131033230012117 in words is "one hundred thirty-one trillion, thirty-three billion, two hundred thirty million, twelve thousand, one hundred seventeen".
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