Base | Representation |
---|---|
bin | 11101110010110011000001… |
… | …001010111010110100110011 |
3 | 122011221201220221111021211012 |
4 | 131302303001022322310303 |
5 | 114133330320400201233 |
6 | 1142404122544541135 |
7 | 36412621141246631 |
oct | 3562630112726463 |
9 | 564851827437735 |
10 | 131034103131443 |
11 | 3882a284190576 |
12 | 128433540217ab |
13 | 5816603006435 |
14 | 245012796c351 |
15 | 102376ec81548 |
hex | 772cc12bad33 |
131034103131443 has 4 divisors (see below), whose sum is σ = 131034164459640. Its totient is φ = 131034041803248.
The previous prime is 131034103131439. The next prime is 131034103131461. The reversal of 131034103131443 is 344131301430131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131034103131443 - 22 = 131034103131439 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131034103131403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27339005 + ... + 31772462.
It is an arithmetic number, because the mean of its divisors is an integer number (32758541114910).
Almost surely, 2131034103131443 is an apocalyptic number.
131034103131443 is a deficient number, since it is larger than the sum of its proper divisors (61328197).
131034103131443 is an equidigital number, since it uses as much as digits as its factorization.
131034103131443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61328196.
The product of its (nonzero) digits is 15552, while the sum is 32.
Adding to 131034103131443 its reverse (344131301430131), we get a palindrome (475165404561574).
The spelling of 131034103131443 in words is "one hundred thirty-one trillion, thirty-four billion, one hundred three million, one hundred thirty-one thousand, four hundred forty-three".
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