Base | Representation |
---|---|
bin | 111101000001010011… |
… | …0010100100000110111 |
3 | 110112020102001220221222 |
4 | 1322002212110200313 |
5 | 4121332231234310 |
6 | 140110552100555 |
7 | 12316203331013 |
oct | 1720246244067 |
9 | 415212056858 |
10 | 131040102455 |
11 | 506347a3539 |
12 | 2149109475b |
13 | c484513082 |
14 | 64b1695543 |
15 | 361e317055 |
hex | 1e82994837 |
131040102455 has 4 divisors (see below), whose sum is σ = 157248122952. Its totient is φ = 104832081960.
The previous prime is 131040102433. The next prime is 131040102469. The reversal of 131040102455 is 554201040131.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 131040102455 - 214 = 131040086071 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13104010241 + ... + 13104010250.
It is an arithmetic number, because the mean of its divisors is an integer number (39312030738).
Almost surely, 2131040102455 is an apocalyptic number.
131040102455 is a deficient number, since it is larger than the sum of its proper divisors (26208020497).
131040102455 is an equidigital number, since it uses as much as digits as its factorization.
131040102455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26208020496.
The product of its (nonzero) digits is 2400, while the sum is 26.
Adding to 131040102455 its reverse (554201040131), we get a palindrome (685241142586).
The spelling of 131040102455 in words is "one hundred thirty-one billion, forty million, one hundred two thousand, four hundred fifty-five".
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