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1310401044445 = 5262080208889
BaseRepresentation
bin10011000100011001111…
…111010001111111011101
311122021101002202020220111
4103010121333101333131
5132432200131410240
62441553454050021
7163446650045203
oct23043177217735
94567332666814
101310401044445
11465813255899
12191b6a7a9911
1396754c006cc
14475d0aa5073
15241471011ea
hex13119fd1fdd

1310401044445 has 4 divisors (see below), whose sum is σ = 1572481253340. Its totient is φ = 1048320835552.

The previous prime is 1310401044427. The next prime is 1310401044457. The reversal of 1310401044445 is 5444401040131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 140635500196 + 1169765544249 = 375014^2 + 1081557^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310401044445 - 227 = 1310266826717 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131040104440 + ... + 131040104449.

It is an arithmetic number, because the mean of its divisors is an integer number (393120313335).

Almost surely, 21310401044445 is an apocalyptic number.

It is an amenable number.

1310401044445 is a deficient number, since it is larger than the sum of its proper divisors (262080208895).

1310401044445 is an equidigital number, since it uses as much as digits as its factorization.

1310401044445 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 262080208894.

The product of its (nonzero) digits is 15360, while the sum is 31.

Adding to 1310401044445 its reverse (5444401040131), we get a palindrome (6754802084576).

The spelling of 1310401044445 in words is "one trillion, three hundred ten billion, four hundred one million, forty-four thousand, four hundred forty-five".

Divisors: 1 5 262080208889 1310401044445