131040110142313 has 4 divisors (see below), whose sum is σ = 137936958044560. Its totient is φ = 124143262240068.

The previous prime is 131040110142311. The next prime is 131040110142323. The reversal of 131040110142313 is 313241011040131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 131040110142313 - 2¹ = 131040110142311 is a prime.

It is a super-2 number, since 2×131040110142313² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131040110142311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3448423951095 + ... + 3448423951132.

It is an arithmetic number, because the mean of its divisors is an integer number (34484239511140).

Almost surely, 2^{131040110142313} is an apocalyptic number.

It is an amenable number.

131040110142313 is a deficient number, since it is larger than the sum of its proper divisors (6896847902247).

131040110142313 is an equidigital number, since it uses as much as digits as its factorization.

131040110142313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6896847902246.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 131040110142313 its reverse (313241011040131), we get a palindrome (444281121182444).

The spelling of 131040110142313 in words is "one hundred thirty-one trillion, forty billion, one hundred ten million, one hundred forty-two thousand, three hundred thirteen".