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1310402135143 = 2714835432233
BaseRepresentation
bin10011000100011010000…
…011011100010001100111
311122021101011210200001201
4103010122003130101213
5132432200421311033
62441553533303331
7163446662240113
oct23043203342147
94567334720051
101310402135143
114658139302a2
12191b6b034b47
13967551c2caa
14475d0caa743
152414726947d
hex1311a0dc467

1310402135143 has 4 divisors (see below), whose sum is σ = 1315237567648. Its totient is φ = 1305566702640.

The previous prime is 1310402135099. The next prime is 1310402135149. The reversal of 1310402135143 is 3415312040131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1310402135143 - 233 = 1301812200551 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310402135149) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2417715846 + ... + 2417716387.

It is an arithmetic number, because the mean of its divisors is an integer number (328809391912).

Almost surely, 21310402135143 is an apocalyptic number.

1310402135143 is a deficient number, since it is larger than the sum of its proper divisors (4835432505).

1310402135143 is an equidigital number, since it uses as much as digits as its factorization.

1310402135143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4835432504.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 1310402135143 its reverse (3415312040131), we get a palindrome (4725714175274).

The spelling of 1310402135143 in words is "one trillion, three hundred ten billion, four hundred two million, one hundred thirty-five thousand, one hundred forty-three".

Divisors: 1 271 4835432233 1310402135143