Base | Representation |
---|---|
bin | 1011111010110000010100… |
… | …1111011001111001100111 |
3 | 1201101201210121012211120120 |
4 | 2332230011033121321213 |
5 | 3204144024441110143 |
6 | 43511524255533023 |
7 | 2521510104626424 |
oct | 276540517317147 |
9 | 51351717184516 |
10 | 13104033144423 |
11 | 41a24310a7a01 |
12 | 157779622a173 |
13 | 740921c22840 |
14 | 33434a986d4b |
15 | 17acec9e2383 |
hex | beb053d9e67 |
13104033144423 has 8 divisors (see below), whose sum is σ = 18816047592048. Its totient is φ = 8064020396544.
The previous prime is 13104033144413. The next prime is 13104033144443. The reversal of 13104033144423 is 32444133040131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13104033144423 - 24 = 13104033144407 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13104033144413) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 168000424890 + ... + 168000424967.
It is an arithmetic number, because the mean of its divisors is an integer number (2352005949006).
Almost surely, 213104033144423 is an apocalyptic number.
13104033144423 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13104033144423 is a deficient number, since it is larger than the sum of its proper divisors (5712014447625).
13104033144423 is a wasteful number, since it uses less digits than its factorization.
13104033144423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 336000849873.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 13104033144423 its reverse (32444133040131), we get a palindrome (45548166184554).
The spelling of 13104033144423 in words is "thirteen trillion, one hundred four billion, thirty-three million, one hundred forty-four thousand, four hundred twenty-three".
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