13104040113 has 24 divisors (see below), whose sum is σ = 20783756448. Its totient is φ = 8222140224.

The previous prime is 13104040097. The next prime is 13104040177. The reversal of 13104040113 is 31104040131.

It is not a de Polignac number, because 13104040113 - 2⁴ = 13104040097 is a prime.

It is a super-2 number, since 2×13104040113² (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13104040193) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1581931 + ... + 1590192.

It is an arithmetic number, because the mean of its divisors is an integer number (865989852).

Almost surely, 2^13104040113 is an apocalyptic number.

It is an amenable number.

13104040113 is a deficient number, since it is larger than the sum of its proper divisors (7679716335).

13104040113 is an equidigital number, since it uses as much as digits as its factorization.

13104040113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3172155 (or 3172143 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 13104040113 its sum of digits (18), we get a palindrome (13104040131).

Adding to 13104040113 its reverse (31104040131), we get a palindrome (44208080244).

The spelling of 13104040113 in words is "thirteen billion, one hundred four million, forty thousand, one hundred thirteen".