Base | Representation |
---|---|
bin | 10011000100011010100… |
… | …001111100111010001011 |
3 | 11122021101201212000020111 |
4 | 103010122201330322023 |
5 | 132432204443230011 |
6 | 2441554420535151 |
7 | 163450120230631 |
oct | 23043241747213 |
9 | 4567351760214 |
10 | 1310410133131 |
11 | 4658183a3300 |
12 | 191b718514b7 |
13 | 96756a63528 |
14 | 475d1d8d351 |
15 | 24147ce9121 |
hex | 1311a87ce8b |
1310410133131 has 24 divisors (see below), whose sum is σ = 1462761387360. Its totient is φ = 1172894997120.
The previous prime is 1310410133047. The next prime is 1310410133141. The reversal of 1310410133131 is 1313310140131.
It is not a de Polignac number, because 1310410133131 - 211 = 1310410131083 is a prime.
It is a super-2 number, since 2×13104101331312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1310410133141) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1852215 + ... + 2459983.
It is an arithmetic number, because the mean of its divisors is an integer number (60948391140).
Almost surely, 21310410133131 is an apocalyptic number.
1310410133131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1310410133131 is a deficient number, since it is larger than the sum of its proper divisors (152351254229).
1310410133131 is a wasteful number, since it uses less digits than its factorization.
1310410133131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 608067 (or 608056 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 1310410133131 its reverse (1313310140131), we get a palindrome (2623720273262).
The spelling of 1310410133131 in words is "one trillion, three hundred ten billion, four hundred ten million, one hundred thirty-three thousand, one hundred thirty-one".
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