Base | Representation |
---|---|
bin | 1011111010110000100101… |
… | …0111101011011001011111 |
3 | 1201101201222102120111200212 |
4 | 2332230021113223121133 |
5 | 3204144200210001421 |
6 | 43511535212443035 |
7 | 2521511605524251 |
oct | 276541127533137 |
9 | 51351872514625 |
10 | 13104102422111 |
11 | 41a2467215298 |
12 | 15777b547947b |
13 | 74093339a65c |
14 | 334355c5bcd1 |
15 | 17ad03b28e5b |
hex | beb095eb65f |
13104102422111 has 4 divisors (see below), whose sum is σ = 13187568042792. Its totient is φ = 13020636801432.
The previous prime is 13104102422107. The next prime is 13104102422123. The reversal of 13104102422111 is 11122420140131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13104102422111 - 22 = 13104102422107 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13104102422161) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41732810105 + ... + 41732810418.
It is an arithmetic number, because the mean of its divisors is an integer number (3296892010698).
Almost surely, 213104102422111 is an apocalyptic number.
13104102422111 is a deficient number, since it is larger than the sum of its proper divisors (83465620681).
13104102422111 is an equidigital number, since it uses as much as digits as its factorization.
13104102422111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 83465620680.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 13104102422111 its reverse (11122420140131), we get a palindrome (24226522562242).
The spelling of 13104102422111 in words is "thirteen trillion, one hundred four billion, one hundred two million, four hundred twenty-two thousand, one hundred eleven".
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