Base | Representation |
---|---|
bin | 1011111010110000100101… |
… | …1000001011001011101100 |
3 | 1201101201222102211010021200 |
4 | 2332230021120023023230 |
5 | 3204144200223133200 |
6 | 43511535215325500 |
7 | 2521511606605644 |
oct | 276541130131354 |
9 | 51351872733250 |
10 | 13104102552300 |
11 | 41a24672a4091 |
12 | 15777b5520890 |
13 | 7409334149a6 |
14 | 334355c93524 |
15 | 17ad03b52800 |
hex | beb0960b2ec |
13104102552300 has 216 divisors, whose sum is σ = 43496942173776. Its totient is φ = 3288363233280.
The previous prime is 13104102552287. The next prime is 13104102552367. The reversal of 13104102552300 is 325520140131.
13104102552300 is a `hidden beast` number, since 1 + 3 + 1 + 0 + 4 + 102 + 552 + 3 + 0 + 0 = 666.
13104102552300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 104022952 + ... + 104148848.
It is an arithmetic number, because the mean of its divisors is an integer number (201374732286).
Almost surely, 213104102552300 is an apocalyptic number.
13104102552300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13104102552300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21748471086888).
13104102552300 is an abundant number, since it is smaller than the sum of its proper divisors (30392839621476).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13104102552300 is a wasteful number, since it uses less digits than its factorization.
13104102552300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 132737 (or 132727 counting only the distinct ones).
The product of its (nonzero) digits is 3600, while the sum is 27.
Adding to 13104102552300 its reverse (325520140131), we get a palindrome (13429622692431).
The spelling of 13104102552300 in words is "thirteen trillion, one hundred four billion, one hundred two million, five hundred fifty-two thousand, three hundred".
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