131041114233133 has 16 divisors (see below), whose sum is σ = 141187174934400. Its totient is φ = 120904491847104.

The previous prime is 131041114233101. The next prime is 131041114233143. The reversal of 131041114233133 is 331332411140131.

It is a cyclic number.

It is not a de Polignac number, because 131041114233133 - 2⁵ = 131041114233101 is a prime.

It is a super-2 number, since 2×131041114233133² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131041114233095 and 131041114233104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131041114233143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 239613360 + ... + 240159622.

It is an arithmetic number, because the mean of its divisors is an integer number (8824198433400).

Almost surely, 2^{131041114233133} is an apocalyptic number.

131041114233133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

131041114233133 is a deficient number, since it is larger than the sum of its proper divisors (10146060701267).

131041114233133 is a wasteful number, since it uses less digits than its factorization.

131041114233133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 554868.

The product of its (nonzero) digits is 7776, while the sum is 31.

Adding to 131041114233133 its reverse (331332411140131), we get a palindrome (462373525373264).

The spelling of 131041114233133 in words is "one hundred thirty-one trillion, forty-one billion, one hundred fourteen million, two hundred thirty-three thousand, one hundred thirty-three".