1310412123331 has 4 divisors (see below), whose sum is σ = 1310414669064. Its totient is φ = 1310409577600.

The previous prime is 1310412123311. The next prime is 1310412123373. The reversal of 1310412123331 is 1333212140131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1310412123331 - 2⁹ = 1310412122819 is a prime.

It is a super-2 number, since 2×1310412123331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1310412123296 and 1310412123305.

It is not an unprimeable number, because it can be changed into a prime (1310412123311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 198430 + ... + 1631011.

It is an arithmetic number, because the mean of its divisors is an integer number (327603667266).

Almost surely, 2^{1310412123331} is an apocalyptic number.

1310412123331 is a deficient number, since it is larger than the sum of its proper divisors (2545733).

1310412123331 is an equidigital number, since it uses as much as digits as its factorization.

1310412123331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2545732.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1310412123331 its reverse (1333212140131), we get a palindrome (2643624263462).

The spelling of 1310412123331 in words is "one trillion, three hundred ten billion, four hundred twelve million, one hundred twenty-three thousand, three hundred thirty-one".