Search a number
-
+
131041344130103 = 1118852676318919
BaseRepresentation
bin11101110010111001110000…
…110001001000110000110111
3122011222102121120201010121202
4131302321300301020300313
5114133440133044130403
61142411321252403115
736413265444601121
oct3562716061106067
9564872546633552
10131041344130103
113883235a57aa90
121284483501649b
1358171b821c924
142450613500211
151023a45802688
hex772e70c48c37

131041344130103 has 8 divisors (see below), whose sum is σ = 142954292046720. Its totient is φ = 119128412621880.

The previous prime is 131041344130007. The next prime is 131041344130139. The reversal of 131041344130103 is 301031443140131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131041344130103 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131041344130903) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17578478 + ... + 23897396.

It is an arithmetic number, because the mean of its divisors is an integer number (17869286505840).

Almost surely, 2131041344130103 is an apocalyptic number.

131041344130103 is a deficient number, since it is larger than the sum of its proper divisors (11912947916617).

131041344130103 is a wasteful number, since it uses less digits than its factorization.

131041344130103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8204197.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 131041344130103 its reverse (301031443140131), we get a palindrome (432072787270234).

The spelling of 131041344130103 in words is "one hundred thirty-one trillion, forty-one billion, three hundred forty-four million, one hundred thirty thousand, one hundred three".

Divisors: 1 11 1885267 6318919 20737937 69508109 11912849466373 131041344130103