Base | Representation |
---|---|
bin | 1011111010110000111101… |
… | …0011101100010001010101 |
3 | 1201101202020101000122022022 |
4 | 2332230033103230101111 |
5 | 3204144401210243110 |
6 | 43511553131542525 |
7 | 2521514225336510 |
oct | 276541723542125 |
9 | 51352211018268 |
10 | 13104202040405 |
11 | 41a2508475a63 |
12 | 15778228baa45 |
13 | 74094ac094a8 |
14 | 33436518dd77 |
15 | 17ad0c755755 |
hex | beb0f4ec455 |
13104202040405 has 16 divisors (see below), whose sum is σ = 18198964139520. Its totient is φ = 8871995014272.
The previous prime is 13104202040401. The next prime is 13104202040429. The reversal of 13104202040405 is 50404020240131.
It is a cyclic number.
It is not a de Polignac number, because 13104202040405 - 22 = 13104202040401 is a prime.
It is a super-2 number, since 2×131042020404052 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13104202040401) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2369654024 + ... + 2369659553.
It is an arithmetic number, because the mean of its divisors is an integer number (1137435258720).
Almost surely, 213104202040405 is an apocalyptic number.
It is an amenable number.
13104202040405 is a deficient number, since it is larger than the sum of its proper divisors (5094762099115).
13104202040405 is an equidigital number, since it uses as much as digits as its factorization.
13104202040405 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4739313668.
The product of its (nonzero) digits is 3840, while the sum is 26.
Adding to 13104202040405 its reverse (50404020240131), we get a palindrome (63508222280536).
The spelling of 13104202040405 in words is "thirteen trillion, one hundred four billion, two hundred two million, forty thousand, four hundred five".
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