Base | Representation |
---|---|
bin | 10011000100011011001… |
… | …101001000110010110010 |
3 | 11122021102112011011120000 |
4 | 103010123031020302302 |
5 | 132432220343012002 |
6 | 2441555503330430 |
7 | 163450315401243 |
oct | 23043315106262 |
9 | 4567375134500 |
10 | 1310421454002 |
11 | 4658238258a1 |
12 | 191b755b0a16 |
13 | 967591c837b |
14 | 475d3698cca |
15 | 24148cd361c |
hex | 1311b348cb2 |
1310421454002 has 20 divisors (see below), whose sum is σ = 2936314739886. Its totient is φ = 436807151280.
The previous prime is 1310421453983. The next prime is 1310421454033. The reversal of 1310421454002 is 2004541240131.
1310421454002 is a `hidden beast` number, since 1 + 3 + 104 + 2 + 14 + 540 + 0 + 2 = 666.
It can be written as a sum of positive squares in only one way, i.e., 835781752521 + 474639701481 = 914211^2 + 688941^2 .
It is a Harshad number since it is a multiple of its sum of digits (27).
It is an unprimeable number.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 4044510499 + ... + 4044510822.
Almost surely, 21310421454002 is an apocalyptic number.
1310421454002 is an abundant number, since it is smaller than the sum of its proper divisors (1625893285884).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1310421454002 is an equidigital number, since it uses as much as digits as its factorization.
1310421454002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8089021335 (or 8089021326 counting only the distinct ones).
The product of its (nonzero) digits is 3840, while the sum is 27.
Adding to 1310421454002 its reverse (2004541240131), we get a palindrome (3314962694133).
The spelling of 1310421454002 in words is "one trillion, three hundred ten billion, four hundred twenty-one million, four hundred fifty-four thousand, two".
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