Base | Representation |
---|---|
bin | 10011000100011011011… |
… | …000000101010010100011 |
3 | 11122021102201112221101220 |
4 | 103010123120011102203 |
5 | 132432222111320420 |
6 | 2442000045030123 |
7 | 163450351651326 |
oct | 23043330052243 |
9 | 4567381487356 |
10 | 1310424323235 |
11 | 465825405565 |
12 | 191b76555343 |
13 | 96759991341 |
14 | 475d3c047bd |
15 | 2414919d840 |
hex | 1311b6054a3 |
1310424323235 has 32 divisors (see below), whose sum is σ = 2117260374528. Its totient is φ = 692033932800.
The previous prime is 1310424323227. The next prime is 1310424323267. The reversal of 1310424323235 is 5323234240131.
It is not a de Polignac number, because 1310424323235 - 23 = 1310424323227 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1310424323196 and 1310424323205.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16415979 + ... + 16495611.
It is an arithmetic number, because the mean of its divisors is an integer number (66164386704).
Almost surely, 21310424323235 is an apocalyptic number.
1310424323235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1310424323235 is a deficient number, since it is larger than the sum of its proper divisors (806836051293).
1310424323235 is a wasteful number, since it uses less digits than its factorization.
1310424323235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 90395.
The product of its (nonzero) digits is 51840, while the sum is 33.
Adding to 1310424323235 its reverse (5323234240131), we get a palindrome (6633658563366).
The spelling of 1310424323235 in words is "one trillion, three hundred ten billion, four hundred twenty-four million, three hundred twenty-three thousand, two hundred thirty-five".
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