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131043000000 = 26356112192
BaseRepresentation
bin111101000001011000…
…1010111111011000000
3110112020121112010122110
41322002301113323000
54121334002000000
6140111134135320
712316240056453
oct1720261277300
9415217463573
10131043000000
11506363a2500
1221492051540
13c484cb8bb3
1464b1c0b49a
15361e6da850
hex1e82c57ec0

131043000000 has 882 divisors, whose sum is σ = 502764736404. Its totient is φ = 30096000000.

The previous prime is 131042999963. The next prime is 131043000007. The reversal of 131043000000 is 340131.

131043000000 is digitally balanced in base 7, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a self number, because there is not a number n which added to its sum of digits gives 131043000000.

It is not an unprimeable number, because it can be changed into a prime (131043000007) by changing a digit.

It is a polite number, since it can be written in 125 ways as a sum of consecutive naturals, for example, 6896999991 + ... + 6897000009.

Almost surely, 2131043000000 is an apocalyptic number.

131043000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131043000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (251382368202).

131043000000 is an abundant number, since it is smaller than the sum of its proper divisors (371721736404).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131043000000 is an frugal number, since it uses more digits than its factorization.

131043000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 105 (or 40 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 12.

Multiplying 131043000000 by its sum of digits (12), we get a square (1572516000000 = 12540002).

131043000000 divided by its sum of digits (12) gives a square (10920250000 = 1045002).

Adding to 131043000000 its reverse (340131), we get a palindrome (131043340131).

The spelling of 131043000000 in words is "one hundred thirty-one billion, forty-three million", and thus it is an aban number.