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13104310443234 = 232184051740539
BaseRepresentation
bin1011111010110001010111…
…0001001101110011100010
31201101202111221000002000220
42332230111301031303202
53204200111433140414
643512012003223510
72521520012626653
oct276542561156342
951352457002026
1013104310443234
1141a256368667a
121577853077b96
1374096750288a
1433437572b52a
1517ad17019ca9
hexbeb15c4dce2

13104310443234 has 8 divisors (see below), whose sum is σ = 26208620886480. Its totient is φ = 4368103481076.

The previous prime is 13104310443199. The next prime is 13104310443271. The reversal of 13104310443234 is 43234401340131.

It is a sphenic number, since it is the product of 3 distinct primes.

13104310443234 is an admirable number.

It is a junction number, because it is equal to n+sod(n) for n = 13104310443195 and 13104310443204.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1092025870264 + ... + 1092025870275.

It is an arithmetic number, because the mean of its divisors is an integer number (3276077610810).

Almost surely, 213104310443234 is an apocalyptic number.

13104310443234 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13104310443234 is a wasteful number, since it uses less digits than its factorization.

13104310443234 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2184051740544.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 13104310443234 its reverse (43234401340131), we get a palindrome (56338711783365).

The spelling of 13104310443234 in words is "thirteen trillion, one hundred four billion, three hundred ten million, four hundred forty-three thousand, two hundred thirty-four".

Divisors: 1 2 3 6 2184051740539 4368103481078 6552155221617 13104310443234