Base | Representation |
---|---|
bin | 11101110010111011011111… |
… | …101001101010011110100111 |
3 | 122011222121102020012202211020 |
4 | 131302323133221222132213 |
5 | 114134002440314121043 |
6 | 1142412230025342223 |
7 | 36413362524152046 |
oct | 3562733751523647 |
9 | 564877366182736 |
10 | 131043204442023 |
11 | 38833124688955 |
12 | 12845074037973 |
13 | 5817423768903 |
14 | 245074c5d655d |
15 | 1023b03cc0e83 |
hex | 772edfa6a7a7 |
131043204442023 has 16 divisors (see below), whose sum is σ = 177843619209216. Its totient is φ = 85816084586400.
The previous prime is 131043204441997. The next prime is 131043204442123. The reversal of 131043204442023 is 320244402340131.
It is not a de Polignac number, because 131043204442023 - 25 = 131043204441991 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131043204442123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1702661611 + ... + 1702738572.
It is an arithmetic number, because the mean of its divisors is an integer number (11115226200576).
Almost surely, 2131043204442023 is an apocalyptic number.
131043204442023 is a deficient number, since it is larger than the sum of its proper divisors (46800414767193).
131043204442023 is a wasteful number, since it uses less digits than its factorization.
131043204442023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3405400414.
The product of its (nonzero) digits is 55296, while the sum is 33.
Adding to 131043204442023 its reverse (320244402340131), we get a palindrome (451287606782154).
The spelling of 131043204442023 in words is "one hundred thirty-one trillion, forty-three billion, two hundred four million, four hundred forty-two thousand, twenty-three".
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