Base | Representation |
---|---|
bin | 1011111010110001011010… |
… | …1010101100010000001011 |
3 | 1201101202112222100112222000 |
4 | 2332230112222230100023 |
5 | 3204200124312311110 |
6 | 43512013302202043 |
7 | 2521520254661565 |
oct | 276542652542013 |
9 | 51352488315860 |
10 | 13104325510155 |
11 | 41a2571137680 |
12 | 1577858123323 |
13 | 74096a679809 |
14 | 334377730335 |
15 | 17ad184e41c0 |
hex | beb16aac40b |
13104325510155 has 64 divisors (see below), whose sum is σ = 25534897712640. Its totient is φ = 6323500310400.
The previous prime is 13104325510153. The next prime is 13104325510163. The reversal of 13104325510155 is 55101552340131.
13104325510155 is a `hidden beast` number, since 1 + 3 + 10 + 43 + 2 + 551 + 0 + 1 + 55 = 666.
13104325510155 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13104325510155 - 21 = 13104325510153 is a prime.
It is a super-3 number, since 3×131043255101553 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (13104325510153) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 20597712 + ... + 21224381.
It is an arithmetic number, because the mean of its divisors is an integer number (398982776760).
Almost surely, 213104325510155 is an apocalyptic number.
13104325510155 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13104325510155 is a deficient number, since it is larger than the sum of its proper divisors (12430572202485).
13104325510155 is a wasteful number, since it uses less digits than its factorization.
13104325510155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41822329 (or 41822323 counting only the distinct ones).
The product of its (nonzero) digits is 45000, while the sum is 36.
Adding to 13104325510155 its reverse (55101552340131), we get a palindrome (68205877850286).
The spelling of 13104325510155 in words is "thirteen trillion, one hundred four billion, three hundred twenty-five million, five hundred ten thousand, one hundred fifty-five".
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