Base | Representation |
---|---|
bin | 11101110010111011100110… |
… | …001101001000111111101011 |
3 | 122011222121200220010111011020 |
4 | 131302323212031020333223 |
5 | 114134003201441432410 |
6 | 1142412244554303523 |
7 | 36413365330631622 |
oct | 3562734615107753 |
9 | 564877626114136 |
10 | 131043314405355 |
11 | 38833180764a40 |
12 | 128450a4a27ba3 |
13 | 581744048a381 |
14 | 245075d05c6b9 |
15 | 1023b0d792a70 |
hex | 772ee6348feb |
131043314405355 has 64 divisors (see below), whose sum is σ = 236697548613120. Its totient is φ = 61324470144000.
The previous prime is 131043314405347. The next prime is 131043314405401. The reversal of 131043314405355 is 553504413340131.
It is not a de Polignac number, because 131043314405355 - 23 = 131043314405347 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 9493080 + ... + 18767130.
It is an arithmetic number, because the mean of its divisors is an integer number (3698399197080).
Almost surely, 2131043314405355 is an apocalyptic number.
131043314405355 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
131043314405355 is a deficient number, since it is larger than the sum of its proper divisors (105654234207765).
131043314405355 is a wasteful number, since it uses less digits than its factorization.
131043314405355 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9277052.
The product of its (nonzero) digits is 648000, while the sum is 42.
Adding to 131043314405355 its reverse (553504413340131), we get a palindrome (684547727745486).
The spelling of 131043314405355 in words is "one hundred thirty-one trillion, forty-three billion, three hundred fourteen million, four hundred five thousand, three hundred fifty-five".
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