Base | Representation |
---|---|
bin | 1011111010110001011100… |
… | …0100010111101000100001 |
3 | 1201101202120110000112112220 |
4 | 2332230113010113220201 |
5 | 3204200133023211231 |
6 | 43512014102341253 |
7 | 2521520366125410 |
oct | 276542704275041 |
9 | 51352513015486 |
10 | 13104332241441 |
11 | 41a2574a14a21 |
12 | 157785a42a829 |
13 | 74096bb9561c |
14 | 3343785a3477 |
15 | 17ad18dc3896 |
hex | beb17117a21 |
13104332241441 has 16 divisors (see below), whose sum is σ = 19968556992384. Its totient is φ = 7488170832384.
The previous prime is 13104332241439. The next prime is 13104332241479. The reversal of 13104332241441 is 14414223340131.
It is a happy number.
13104332241441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13104332241441 - 21 = 13104332241439 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13104332241431) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14880855 + ... + 15736851.
It is an arithmetic number, because the mean of its divisors is an integer number (1248034812024).
Almost surely, 213104332241441 is an apocalyptic number.
It is an amenable number.
13104332241441 is a deficient number, since it is larger than the sum of its proper divisors (6864224750943).
13104332241441 is an equidigital number, since it uses as much as digits as its factorization.
13104332241441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1585000.
The product of its (nonzero) digits is 27648, while the sum is 33.
Adding to 13104332241441 its reverse (14414223340131), we get a palindrome (27518555581572).
The spelling of 13104332241441 in words is "thirteen trillion, one hundred four billion, three hundred thirty-two million, two hundred forty-one thousand, four hundred forty-one".
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