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13104333020041 = 23647880608361
BaseRepresentation
bin1011111010110001011100…
…0111010101101110001001
31201101202120111111002120221
42332230113013111232021
53204200133223120131
643512014131150041
72521520405550364
oct276542707255611
951352514432527
1013104333020041
1141a25753a699a
12157785a745321
1374096c0a8b33
143343787270db
1517ad18ec9411
hexbeb171d5b89

13104333020041 has 8 divisors (see below), whose sum is σ = 13695221245824. Its totient is φ = 12515206012320.

The previous prime is 13104333020039. The next prime is 13104333020047. The reversal of 13104333020041 is 14002033340131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13104333020041 - 21 = 13104333020039 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13104333019988 and 13104333020015.

It is not an unprimeable number, because it can be changed into a prime (13104333020047) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 440289300 + ... + 440319061.

It is an arithmetic number, because the mean of its divisors is an integer number (1711902655728).

Almost surely, 213104333020041 is an apocalyptic number.

It is an amenable number.

13104333020041 is a deficient number, since it is larger than the sum of its proper divisors (590888225783).

13104333020041 is an equidigital number, since it uses as much as digits as its factorization.

13104333020041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 880609031.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13104333020041 its reverse (14002033340131), we get a palindrome (27106366360172).

The spelling of 13104333020041 in words is "thirteen trillion, one hundred four billion, three hundred thirty-three million, twenty thousand, forty-one".

Divisors: 1 23 647 14881 880608361 20253992303 569753609567 13104333020041