13104400131241 has 4 divisors (see below), whose sum is σ = 13104768547332. Its totient is φ = 13104031715152.

The previous prime is 13104400131233. The next prime is 13104400131247. The reversal of 13104400131241 is 14213100440131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2630089280025 + 10474310851216 = 1621755^2 + 3236404^2 .

It is a cyclic number.

It is not a de Polignac number, because 13104400131241 - 2³ = 13104400131233 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13104400131247) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 184154686 + ... + 184225831.

It is an arithmetic number, because the mean of its divisors is an integer number (3276192136833).

Almost surely, 2^{13104400131241} is an apocalyptic number.

It is an amenable number.

13104400131241 is a deficient number, since it is larger than the sum of its proper divisors (368416091).

13104400131241 is an equidigital number, since it uses as much as digits as its factorization.

13104400131241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 368416090.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 13104400131241 its reverse (14213100440131), we get a palindrome (27317500571372).

The spelling of 13104400131241 in words is "thirteen trillion, one hundred four billion, four hundred million, one hundred thirty-one thousand, two hundred forty-one".