13104403025111 has 8 divisors (see below), whose sum is σ = 13284392450304. Its totient is φ = 12924426493440.

The previous prime is 13104403025083. The next prime is 13104403025123. The reversal of 13104403025111 is 11152030440131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13104403025111 - 2¹⁴ = 13104403008727 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13104403021111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1167770 + ... + 5250951.

It is an arithmetic number, because the mean of its divisors is an integer number (1660549056288).

Almost surely, 2^{13104403025111} is an apocalyptic number.

13104403025111 is a deficient number, since it is larger than the sum of its proper divisors (179989425193).

13104403025111 is an equidigital number, since it uses as much as digits as its factorization.

13104403025111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6446761.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 13104403025111 its reverse (11152030440131), we get a palindrome (24256433465242).

The spelling of 13104403025111 in words is "thirteen trillion, one hundred four billion, four hundred three million, twenty-five thousand, one hundred eleven".