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13104403134523 = 21162106175993
BaseRepresentation
bin1011111010110001101101…
…0010110011100000111011
31201101202202101102021120121
42332230123102303200323
53204200304200301043
643512025114034111
72521522216531651
oct276543322634073
951352671367517
1013104403134523
1141a2600a35a48
12157787a118937
137409807877ac
14334383b78dd1
1517ad20228ded
hexbeb1b4b383b

13104403134523 has 4 divisors (see below), whose sum is σ = 13166509310728. Its totient is φ = 13042296958320.

The previous prime is 13104403134503. The next prime is 13104403134539. The reversal of 13104403134523 is 32543130440131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13104403134523 - 217 = 13104403003451 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13104403134503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31053087786 + ... + 31053088207.

It is an arithmetic number, because the mean of its divisors is an integer number (3291627327682).

Almost surely, 213104403134523 is an apocalyptic number.

13104403134523 is a deficient number, since it is larger than the sum of its proper divisors (62106176205).

13104403134523 is an equidigital number, since it uses as much as digits as its factorization.

13104403134523 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62106176204.

The product of its (nonzero) digits is 51840, while the sum is 34.

Adding to 13104403134523 its reverse (32543130440131), we get a palindrome (45647533574654).

The spelling of 13104403134523 in words is "thirteen trillion, one hundred four billion, four hundred three million, one hundred thirty-four thousand, five hundred twenty-three".

Divisors: 1 211 62106175993 13104403134523