Base | Representation |
---|---|
bin | 1011111010110001101101… |
… | …0010110011100000111011 |
3 | 1201101202202101102021120121 |
4 | 2332230123102303200323 |
5 | 3204200304200301043 |
6 | 43512025114034111 |
7 | 2521522216531651 |
oct | 276543322634073 |
9 | 51352671367517 |
10 | 13104403134523 |
11 | 41a2600a35a48 |
12 | 157787a118937 |
13 | 7409807877ac |
14 | 334383b78dd1 |
15 | 17ad20228ded |
hex | beb1b4b383b |
13104403134523 has 4 divisors (see below), whose sum is σ = 13166509310728. Its totient is φ = 13042296958320.
The previous prime is 13104403134503. The next prime is 13104403134539. The reversal of 13104403134523 is 32543130440131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13104403134523 - 217 = 13104403003451 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13104403134503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31053087786 + ... + 31053088207.
It is an arithmetic number, because the mean of its divisors is an integer number (3291627327682).
Almost surely, 213104403134523 is an apocalyptic number.
13104403134523 is a deficient number, since it is larger than the sum of its proper divisors (62106176205).
13104403134523 is an equidigital number, since it uses as much as digits as its factorization.
13104403134523 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62106176204.
The product of its (nonzero) digits is 51840, while the sum is 34.
Adding to 13104403134523 its reverse (32543130440131), we get a palindrome (45647533574654).
The spelling of 13104403134523 in words is "thirteen trillion, one hundred four billion, four hundred three million, one hundred thirty-four thousand, five hundred twenty-three".
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