13104411021241 has 4 divisors (see below), whose sum is σ = 13104615915252. Its totient is φ = 13104206127232.

The previous prime is 13104411021179. The next prime is 13104411021257. The reversal of 13104411021241 is 14212011440131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4396482174841 + 8707928846400 = 2096779^2 + 2950920^2 .

It is a cyclic number.

It is not a de Polignac number, because 13104411021241 - 2⁷ = 13104411021113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13104411021841) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 102351040 + ... + 102478993.

It is an arithmetic number, because the mean of its divisors is an integer number (3276153978813).

Almost surely, 2^{13104411021241} is an apocalyptic number.

It is an amenable number.

13104411021241 is a deficient number, since it is larger than the sum of its proper divisors (204894011).

13104411021241 is an equidigital number, since it uses as much as digits as its factorization.

13104411021241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 204894010.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 13104411021241 its reverse (14212011440131), we get a palindrome (27316422461372).

The spelling of 13104411021241 in words is "thirteen trillion, one hundred four billion, four hundred eleven million, twenty-one thousand, two hundred forty-one".