Base | Representation |
---|---|
bin | 11101110010111100100010… |
… | …011010000000101011100100 |
3 | 122011222201022021122010222122 |
4 | 131302330202122000223210 |
5 | 114134012234022142012 |
6 | 1142412533114245112 |
7 | 36413432343561035 |
oct | 3562744232005344 |
9 | 564881267563878 |
10 | 131044324412132 |
11 | 388336498a2a8a |
12 | 12845327126798 |
13 | 58175717bc211 |
14 | 2450817252a8c |
15 | 1023b6c29de72 |
hex | 772f22680ae4 |
131044324412132 has 12 divisors (see below), whose sum is σ = 229327738483200. Its totient is φ = 65522113416936.
The previous prime is 131044324412021. The next prime is 131044324412149. The reversal of 131044324412132 is 231214423440131.
It is a super-2 number, since 2×1310443244121322 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131044324412092 and 131044324412101.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5778632 + ... + 17189567.
It is an arithmetic number, because the mean of its divisors is an integer number (19110644873600).
Almost surely, 2131044324412132 is an apocalyptic number.
It is an amenable number.
131044324412132 is a deficient number, since it is larger than the sum of its proper divisors (98283414071068).
131044324412132 is a wasteful number, since it uses less digits than its factorization.
131044324412132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24394570 (or 24394568 counting only the distinct ones).
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 131044324412132 its reverse (231214423440131), we get a palindrome (362258747852263).
The spelling of 131044324412132 in words is "one hundred thirty-one trillion, forty-four billion, three hundred twenty-four million, four hundred twelve thousand, one hundred thirty-two".
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