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13104440532103 = 41319620500783
BaseRepresentation
bin1011111010110001110110…
…0001011101110010000111
31201101202211222210021102011
42332230131201131302013
53204200343234011403
643512032531355051
72521523152440544
oct276543541356207
951352758707364
1013104440532103
1141a2620059338
12157788a752a87
1374098844c93b
14334388b11bcb
1517ad23664a6d
hexbeb1d85dc87

13104440532103 has 4 divisors (see below), whose sum is σ = 13424061032928. Its totient is φ = 12784820031280.

The previous prime is 13104440532101. The next prime is 13104440532119. The reversal of 13104440532103 is 30123504440131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13104440532103 - 21 = 13104440532101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13104440532101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 159810250351 + ... + 159810250432.

It is an arithmetic number, because the mean of its divisors is an integer number (3356015258232).

Almost surely, 213104440532103 is an apocalyptic number.

13104440532103 is a deficient number, since it is larger than the sum of its proper divisors (319620500825).

13104440532103 is an equidigital number, since it uses as much as digits as its factorization.

13104440532103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 319620500824.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 13104440532103 its reverse (30123504440131), we get a palindrome (43227944972234).

The spelling of 13104440532103 in words is "thirteen trillion, one hundred four billion, four hundred forty million, five hundred thirty-two thousand, one hundred three".

Divisors: 1 41 319620500783 13104440532103