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13104441321 = 36971626617
BaseRepresentation
bin11000011010001010…
…11110011111101001
31020211021022121000120
430031011132133221
5203314214110241
610004201353453
7642511625166
oct141505363751
936737277016
1013104441321
11561512a7a4
122658798889
13130ac0bbba
148c459506d
1551a6d2666
hex30d15e7e9

13104441321 has 8 divisors (see below), whose sum is σ = 17475122784. Its totient is φ = 8735027040.

The previous prime is 13104441289. The next prime is 13104441421. The reversal of 13104441321 is 12314440131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13104441321 - 25 = 13104441289 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13104441291 and 13104441300.

It is not an unprimeable number, because it can be changed into a prime (13104441121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 292396 + ... + 334221.

It is an arithmetic number, because the mean of its divisors is an integer number (2184390348).

Almost surely, 213104441321 is an apocalyptic number.

It is an amenable number.

13104441321 is a deficient number, since it is larger than the sum of its proper divisors (4370681463).

13104441321 is an equidigital number, since it uses as much as digits as its factorization.

13104441321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 633591.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 13104441321 its reverse (12314440131), we get a palindrome (25418881452).

The spelling of 13104441321 in words is "thirteen billion, one hundred four million, four hundred forty-one thousand, three hundred twenty-one".

Divisors: 1 3 6971 20913 626617 1879851 4368147107 13104441321