13104442512541 has 4 divisors (see below), whose sum is σ = 13104519282400. Its totient is φ = 13104365742684.

The previous prime is 13104442512533. The next prime is 13104442512547. The reversal of 13104442512541 is 14521524440131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13104442512541 - 2³ = 13104442512533 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13104442512541.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13104442512547) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38128311 + ... + 38470468.

It is an arithmetic number, because the mean of its divisors is an integer number (3276129820600).

Almost surely, 2^{13104442512541} is an apocalyptic number.

It is an amenable number.

13104442512541 is a deficient number, since it is larger than the sum of its proper divisors (76769859).

13104442512541 is an equidigital number, since it uses as much as digits as its factorization.

13104442512541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 76769858.

The product of its (nonzero) digits is 76800, while the sum is 37.

Adding to 13104442512541 its reverse (14521524440131), we get a palindrome (27625966952672).

The spelling of 13104442512541 in words is "thirteen trillion, one hundred four billion, four hundred forty-two million, five hundred twelve thousand, five hundred forty-one".