Base | Representation |
---|---|
bin | 11101110010111101011101… |
… | …111001001101000100111011 |
3 | 122011222210212211121110212012 |
4 | 131302331131321031010323 |
5 | 114134021310021220430 |
6 | 1142413220125440135 |
7 | 36413466152660141 |
oct | 3562753571150473 |
9 | 564883784543765 |
10 | 131045322445115 |
11 | 388340111a2a31 |
12 | 1284556541004b |
13 | 58176a04bac90 |
14 | 24508ada0b591 |
15 | 1023bc9be2695 |
hex | 772f5de4d13b |
131045322445115 has 32 divisors (see below), whose sum is σ = 176715158336640. Its totient is φ = 92563827434496.
The previous prime is 131045322445087. The next prime is 131045322445129. The reversal of 131045322445115 is 511544223540131.
It is a cyclic number.
It is not a de Polignac number, because 131045322445115 - 226 = 131045255336251 is a prime.
It is a super-2 number, since 2×1310453224451152 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 404912981 + ... + 405236489.
It is an arithmetic number, because the mean of its divisors is an integer number (5522348698020).
Almost surely, 2131045322445115 is an apocalyptic number.
131045322445115 is a deficient number, since it is larger than the sum of its proper divisors (45669835891525).
131045322445115 is a wasteful number, since it uses less digits than its factorization.
131045322445115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 594503.
The product of its (nonzero) digits is 288000, while the sum is 41.
Adding to 131045322445115 its reverse (511544223540131), we get a palindrome (642589545985246).
The spelling of 131045322445115 in words is "one hundred thirty-one trillion, forty-five billion, three hundred twenty-two million, four hundred forty-five thousand, one hundred fifteen".
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